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  1. #1
    Member a-parsons's Avatar
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    BMAT paper 2009 (UK)

    <edit by Admin> BMAT Paper Download Removed at Request of Cambridge Assessments </end edit>

    Centres are allowed to retain question papers. These must be collected
    by the invigilator and put into safe storage. Candidates are NOT
    allowed to leave the examination room with a copy of the question
    papers. It is the responsibility of the Head of Centre (or appointed
    invigilator) to keep the question papers in safe storage until 30th
    November 2009 whereupon they can be disposed of, retained by the centre
    or released to candidates.
    Last edited by Admin; 13-11-2009 at 03:15 PM.
    Newcastle University - Conditional, AA - Firm



  2. #2
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    That's a very good idea. Maybe you should keep a note of all of the worked solutions too, not just the correct answers, that way people can learn from others, and also it's easier to challenge incorrect answers (or demonstrate their accuracy)

  3. #3
    Member a-parsons's Avatar
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    Hmm, okay. Editing main post now. (Y)
    Newcastle University - Conditional, AA - Firm

  4. #4
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    Section 2 question 16... I agree with you that it seems odd. I did the following:

    1.) write out the numerator having an index of 3, and the denominator with an index of -4

    = sqrt[(2x10^3+0.8x10^3)/(4x10^-4 + 3000x10^-4)]

    2.) simplify Step 1

    = sqrt[(2+0.8)x10^3/(4+3000)x10^-4]

    3.) bring the 10^-4 up to the numerator (and thus switch the sign, so the numerator is now to the power of 7)

    = sqrt(2.8x10^7/3004)

    4.) bring 2^6 outside of the root (so it becomes 1000)

    = sqrt(28/3004) x 1000

    5.) bring a factor of 4 outside of the root (so it becomes 2)

    = sqrt(7/3004) x 2000

    This is simplified as much as possible. 3004 is not divisible by 7, and the square root of 7 is irrational. I get exactly the same answer as you

  5. #5
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    Quote Originally Posted by Entropy View Post
    Here is my explanation of Q16:
    Explanation

    (Sorry for the awful color, grabbed the first marker I could!)
    Hope it helped anyway.
    Ah, I see what the problem is now - it's the quality of the photocopying

    I (and so did A-Parsons it seems) read the second term in the denominator as 3x10^-1 (and therefore rewritten it as 3000x10^-4), but you've got it as 3x10^-4

    So the "-4" has photocopied to look like a "-1"

  6. #6
    Crims
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    Quote Originally Posted by DLS View Post
    Section 2
    Question 8 - B
    I'll carry on tommoz
    I agree with you completely for questions 2 and 6, but could u elucidate your working for this one? I got A I think, but I might be mistaken... I also take maths in french so the whole "the cube has unit length sides" might have confused me... anyways I'd be glad to understand.
    Thankyou
    Crims

  7. #7
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    Cube has unit sides just means that the length of each side of the cube is 1

  8. #8
    Crims
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    So wasn't the answer A? u use pythagoras and find that 1square + 1 square= c
    c= square root of 2?

  9. #9
    Member a-parsons's Avatar
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    With regards to S2Q16, yes it was bad scanning - I looked at the original paper earlier, and the denominator was in the order -4, not -1. That clears it up, and I can write an explanation fine now. :L

    And don't worry about jumping around all over the place, I can fill them in wherever you want - order doesn't matter.
    Newcastle University - Conditional, AA - Firm

  10. #10
    Junior Member Entropy's Avatar
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    Quote Originally Posted by a-parsons View Post
    And don't worry about jumping around all over the place, I can fill them in wherever you want - order doesn't matter.
    It matters to me!!!


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