BMAT paper 2009 (UK)

[o_O]

thanks for putting this up, i feel slightly better knowing that i did get some questions right, I could only remember the ones i got wrong

[a-parsons]

Entropy, I hope you don't mind, but because it was a difficult one to write out in words, I have posted a link to your workings for S2Q16 (which are beautiful, in all their lilac glory, by the way. :L). However, would you mind rewriting it in darker ink, so it is easier to read (if less pretty)? Oh, I've also used your one for S2Q8.

Thanks for this, everyone who is contributing.

[Entropy]

Entropy, I hope you don't mind, but because it was a difficult one to write out in words, I have posted a link to your workings for S2Q8 (which are beautiful, in all their lilac glory, by the way. :L). However, would you mind rewriting it in darker ink, so it is easier to read (if less pretty)? Oh, I've also used your one for S2Q8.

Thanks for this, everyone who is contributing.

I think you meant rewriting S2Q16. (And lol, I apologized for the lilac-ness. That's the only pen I have in front of me right now!!)
I'm too lazy to rewrite the entire thing, but I played with the picture a little bit and adjusted the saturation.

4 - C
x/x+y+z X y/x+y+z = xy/(x+y+z)^2
Please could someone verify this, and expand upon the explanation, as this is very brief, and I do not understand it enough to explain it myself. Hint hint, Entropy with your pretty diagrams? :L

I don't think this one needs a diagram. And besides, I'm not that great with probability, but C is the answer I chose as well.

[a-parsons]

LESLIE!!! STOP CORRECTING ME!!! Yes, that is what I meant. Gr.

And thanks, it is far more understandable now. :P

And also, why are you not on MSN/AIM, yet you are replying on here? Have you blocked me? :L

[Entropy]

LESLIE!!! STOP CORRECTING ME!!! Yes, that is what I meant. Gr.

And thanks, it is far more understandable now. :P

And also, why are you not on MSN/AI, yet you are replying on here? Have you blocked me? :L

Hahahaha, that took me a second to understand.
No no, I'll be online in a bit.

[a-parsons]

If someone asks "Why are you calling Entropy 'Leslie'?", I may be tempted to post that photo on here... :P

Though I suppose I can't, as you would probably go mental 'cos you are afraid of paedophilles/ stalkers, and stuff like that... :L Bummer. I will juust have to explain it if anyone asks. :P

And as for the horrible probability one, I think all the maths ones need a pretty drawing, but now you've explained it a bit, I might be able to do my own pretty drawing for it... I'll try in a bit.

[Entropy]

If someone asks "Why are you calling Entropy 'Leslie'?", I may be tempted to post that photo on here... :P

Though I suppose I can't, as you would probably go mental 'cos you are afraid of paedophilles/ stalkers, and stuff like that... :L Bummer. I will juust have to explain it if anyone asks. :P

And as for the horrible probability one, I think all the maths ones need a pretty drawing, but now you've explained it a bit, I might be able to do my own pretty drawing for it... I'll try in a bit.

Don't you DARE post that picture up! I will personally have to come to UK and kill you then (regardless of whether I get any interviews).
As for the pretty drawing... well you know, you can ... try. :P

Oh, Chwirkytheappleboy, can you please take a shot at S1Q3?

[Crims]

No, it wasn't just that. You had to actually apply Pythagora's Theorem two times. I find it easier to explain by doing the question instead of using words so here you go:
Explanation for S2Q8.

Hope that helped.

[/I]

I feel like such a tard now... But thx that did help now I know what I did wrong... It's unit side so it's 1 but since it's half cuz the base is vertex etc blablbla u divide that side by two and then the maths logically follows thx again guys. I'll try to contribute this weekend when I have a bit more time^^
Goodnight guys
Crims

[Chwirkytheappleboy]

Oh, Chwirkytheappleboy, can you please take a shot at S1Q3?

Oh yeah, that one's actually pretty easy if you want to do it by a "brute force" method. I guess there must be a more efficient and logical way of doing it, but I chose a method which definitely gets the correct answer even if it is a bit slow. Basically because all of the charts except the correct one have exactly two bars wrong, then you know that once you've got the "correct" chart, then when you compare the others to it, they'll all have exactly two bars which look different. So just pick a random chart, assume it's "correct", and compare all the other charts to it. Then you can start eliminating incorrect answers.

So say we pick an initial guess. Chart A, for example. We assume this is our correct position, but then we notice that when we compare it to Chart C, bars B, C, and E are different. So since 3 bars are "incorrect", Chart A cannot actually be the correct answer.

Carry on, and eventually Chart D seems to be the correct answer;
-> Chart A.) Bars B & C are different
-> Chart B.) Bars B & E are different
-> Chart C.) Bars C & E are different
-> Chart E.) Bars A & D are different

[a-parsons]

Damn, now I have to rewrite that answer in <5 lines... :L I think D was what I put, and I did the same method as you, though less random. I started from chart A, bar 1, then worked my way through. :L